Q.
A train travels from one station to another at a speed of 40km/hour and returns to the first station at a speed of 60km/hour. The average speed and average velocity of the train are respectively
Let S be the distance between two stations
Time taken by train from one station to another,t1=40S hr.
Time taken for returning, t2=60S hr.
Average speed = TotaltimeTotaldistance=40S+60SS+S = 48 km hr−1
Average velocity = timeDisplacement=time0=0
* Shortcut Average speed = υ1+υ22υ1υ2=40+602(40×60) 48 km hr−1