A train T travelling at a speed of 54 kmph passes an electric pole in 20 s. Find the time taken by it to cross a bridge of length 900 m (in seconds).

Question

A train T travelling at a speed of 54 kmph passes an electric pole in 20 s. Find the time taken by it to cross a bridge of length 900 m (in seconds). (A) 60 (B) 50 (C) 40 (D) 80

Tardigrade Admin · Accepted Answer

Let the length of the train be L m. (L/(54)((5)18))=20 (∵ 1 km / h =(5/18) m / s ) text i.e., L=300 text Required time =(L+900/(54)((5)18))=(1200/15) =80 s

Q. A train $T$ travelling at a speed of $54 km p h$ passes an electric pole in 20 s. Find the time taken by it to cross a bridge of length $900 m$ (in seconds).

60

50

40

80

Let the length of the train be $L m$ .
$\frac{L}{( 54 ) ( \frac{5}{18} )} = 20$
$(∵ 1 km / h = \frac{5}{18} m / s) i.e., L = 300$
$Required time = \frac{L + 900}{( 54 ) ( \frac{5}{18} )} = \frac{1200}{15}$
$= 80 s$

Q. A train T travelling at a speed of 54kmph passes an electric pole in 20 s. Find the time taken by it to cross a bridge of length 900m (in seconds).

60

50

40

80

Let the length of the train be Lm. (54)(185​)L​=20 (∵1km/h=185​m/s) i.e., L=300 Required time =(54)(185​)L+900​=151200​ =80s

Q. A train $T$ travelling at a speed of $54 km p h$ passes an electric pole in 20 s. Find the time taken by it to cross a bridge of length $900 m$ (in seconds).

Let the length of the train be $L m$ .
$\frac{L}{( 54 ) ( \frac{5}{18} )} = 20$
$(∵ 1 km / h = \frac{5}{18} m / s) i.e., L = 300$
$Required time = \frac{L + 900}{( 54 ) ( \frac{5}{18} )} = \frac{1200}{15}$
$= 80 s$