A train of 200 m long travelling at 50 m / s overtakes another train 130 m long travelling at 30 m / s. The time taken by the first train to pass the second train is:

Question

A train of 200 m long travelling at 50 m / s overtakes another train 130 m long travelling at 30 m / s. The time taken by the first train to pass the second train is: (A) 15 second (B) 17 second (C) 16.5 second (D) 18 second

Tardigrade Admin · Accepted Answer

Relative velocity of 1 text st train w.r.t 2 text nd =50-30=20 m / s Total distance =130+200=330 Time taken =(330/20)=16.5 seconds

Q. A train of $200 m$ long travelling at $50 m / s$ overtakes another train $130 m$ long travelling at $30 m / s$ . The time taken by the first train to pass the second train is:

15 second

17 second

16.5 second

18 second

Relative velocity of $1^{st}$ train w.r.t $2^{nd} = 50 - 30 = 20 m / s$
Total distance $= 130 + 200 = 330$
Time taken $= \frac{330}{20} = 16.5$ seconds

Q. A train of 200m long travelling at 50m/s overtakes another train 130m long travelling at 30m/s. The time taken by the first train to pass the second train is: