A train moving with a speed of 36 kmph takes 14 s to cross a bridge of length 100 m. The length of the train is

Question

A train moving with a speed of 36 kmph takes 14 s to cross a bridge of length 100 m. The length of the train is (A) 140 m (B) 40 m (C) 100 m (D) 360 m

Tardigrade Admin · Accepted Answer

Here, v = 36 km h-1 = 36 × (5/18) = 10 m s-1 Length of bridge, I = 100 m Time taken by train to cross the bridge, t= 14 s Let the length of the train be x m. ∴ : :: : v = ((x + l)/t) or , x = v × t - l or , x = 10 × 14 = 100 = 40 m

Q. A train moving with a speed of 36 kmph takes 14 s to cross a bridge of length 100 m. The length of the train is

140 m

40 m

100 m

360 m

Here, $v = 36 km h^{- 1} = 36 \times \frac{5}{18} = 10 m s^{- 1}$
Length of bridge, $I = 100 m$
Time taken by train to cross the bridge, $t = 14 s$
Let the length of the train be $x$ m.
$∴ v = \frac{( x + l )}{t}$
or , $x = v \times t - l$ or , $x = 10 \times 14 = 100 = 40 m$

Q. A train moving with a speed of 36 kmph takes 14 s to cross a bridge of length 100 m. The length of the train is

140 m

40 m

100 m

360 m

Here, v=36kmh−1=36×185​=10ms−1 Length of bridge, I=100m Time taken by train to cross the bridge, t=14s Let the length of the train be x m. ∴v=t(x+l)​ or , x=v×t−l or , x=10×14=100=40m

Here, $v = 36 km h^{- 1} = 36 \times \frac{5}{18} = 10 m s^{- 1}$
Length of bridge, $I = 100 m$
Time taken by train to cross the bridge, $t = 14 s$
Let the length of the train be $x$ m.
$∴ v = \frac{( x + l )}{t}$
or , $x = v \times t - l$ or , $x = 10 \times 14 = 100 = 40 m$