Q.
A train 150m long passes a pole in 15s time, and it takes 8s to pass another train of the same length travelling in opposite direction. What is the speed of the second train?
Speed of first train =(15150)secm=10secm
Let the speed of second train be x m/sec.
Relative speed =(10+x)secm . ∴10+x300=8⇔300=80+8x⇔x=5220=255secm .
So, speed of second train =(255×518)kmph=99kmph .