A tin nucleus has charge +50e. If the proton is at 10-12 m from the nucleus, then the potential at this position, is (charge on proton is 1 × 6 × 10-19 C)

Question

A tin nucleus has charge +50e. If the proton is at 10-12 m from the nucleus, then the potential at this position, is (charge on proton is 1 × 6 × 10-19 C) (A) 7.2 × 108 V (B) 14.4 × 104 V (C) 14.4 × 108 V (D) 7.2 × 104 V

Tardigrade Admin · Accepted Answer

Given: Charge (Q) = 50e = 50 × (1 .6Ã10 -19 ) CÍ¾ Distance of proton from nucleus (r) = 10-12 m and charge on proton (e) = 1 .6 × 10-19 C. We know that potential (V)=(1/4π ε0)×((Q/r))=9×109×(50×1Ã6×10-19/10-12) =7.2 × 104 V.

Q. A tin nucleus has charge $+ 50 e$ . If the proton is at $1 0^{- 12} m$ from the nucleus, then the potential at this position, is (charge on proton is $1 \times 6 \times 1 0^{- 19} C)$

$7.2 \times 1 0^{8} V$

$14.4 \times 1 0^{4} V$

$14.4 \times 1 0^{8} V$

$7.2 \times 1 0^{4} V$

Q. A tin nucleus has charge +50e. If the proton is at 10−12m from the nucleus, then the potential at this position, is (charge on proton is 1×6×10−19C)

7.2×108V

14.4×104V

14.4×108V

7.2×104V

Given: Charge (Q)=50e=50×(1.6×10−19)C; Distance of proton from nucleus (r)=10−12m and charge on proton (e)=1.6×10−19C. We know that potential (V)=4πε0​1​×(rQ​)=9×109×10−1250×1×6×10−19​ =7.2×104V.

Q. A tin nucleus has charge $+ 50 e$ . If the proton is at $1 0^{- 12} m$ from the nucleus, then the potential at this position, is (charge on proton is $1 \times 6 \times 1 0^{- 19} C)$

$7.2 \times 1 0^{8} V$

$14.4 \times 1 0^{4} V$

$14.4 \times 1 0^{8} V$

$7.2 \times 1 0^{4} V$