Question

A tin chloride Q undergoes the following reactions (not balanced)
$Q+C{l}^{-}\to X$
$Q+M{e}_{3}N\to Y$
$Q+CuC{l}_2\to Z+CuCl$
X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the correct option(s)

• A. The central atom in $X$ is $s{p}^3$ hybridized
• B. There is a coordinate bond in Y
• C. The oxidation state of the central atom in $Z$ is $+2$
• D. The central atom in Z has one lone pair of electrons

Answer 1

Answer: (A), (B)

Compound Q is $SnC{l}_2$. The given reactions are
$\mathrm{SnCl}{}_2+\mathrm{Cl}{}^{-}\to \underset{\text{(X)}}{\mathrm{SnCl}{}_3^{-}}$
$\mathrm{SnCl}{}_2+\mathrm{Me}{}_3\mathrm{N}\to \underset{\text{(Y)}}{\mathrm{Me}{}_3\mathrm{N}{}^{+}-\mathrm{Sn}{}^{-}\mathrm{Cl}{}_2}$
$\mathrm{SnCl}{}_2+2\mathrm{CuCl}{}_2\to \underset{\text{(Z)}}{\mathrm{SnCl}{}_4+2\mathrm{CuCl}}$
Hybridisation of Sn in $SnC{l}_3^{-}$ is $s{p}^3$
Trimethylamine forms a co-ordinate bond with Sn in $SnC{l}_2$.
There is no lone pair on central atom of $SnC{l}_4(Z)$.