A thin, symmetric double convex lens of power P is cut into three parts A,B and C as shown. The power of -

Question

A thin, symmetric double convex lens of power P is cut into three parts A,B and C as shown. The power of - <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-hw147muxdzzfarws.jpg" /> (A) C is P (B) A is 2P (C) B is (P/2) (D) B is (3/2)P

Tardigrade Admin · Accepted Answer

fB=fc,(1/fA)=(1/fB)+(1/fc)=PB+PC=2PB=P

Q. $A$ thin, symmetric double convex lens of power $P$ is cut into three parts $A, B$ and $C$ as shown. The power of -

$C$ is $P$

$A$ is $2 P$

$B$ is $\frac{P}{2}$

$B$ is $\frac{3}{2} P$

$f_{B} = f_{c}, \frac{1}{f _{A}} = \frac{1}{f _{B}} + \frac{1}{f _{c}} = P_{B} + P_{C} = 2 P_{B} = P$

Q. A thin, symmetric double convex lens of power P is cut into three parts A,B and C as shown. The power of -

C is P

A is 2P

B is 2P​

B is 23​P