A thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the center of the shell. The electric potential at a point P at distance (R/2) from the center of the shell is ( Q =10 μ C , q =-2 μ C )

Question

A thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the center of the shell. The electric potential at a point P at distance (R/2) from the center of the shell is ( Q =10 μ C , q =-2 μ C ) (A) (1.6 × 105/ R ) volt (B) 1.6 × 105 R volt (C) (1.4 × 105/ R ) volt (D) (4 × 10-6/ R ) volt

Tardigrade Admin · Accepted Answer

Electric potential at point P V P =( KQ / r )+( K q / r ) VP=(K Q/(R)2)-(K q/(R)2) VP=(2 K/R)(10-2) 10-6 =(2 × 9 × 109 × 8 × 10-6/ R )=(144 × 103/ R ) volt V P =(1.44 × 105 volt / R )

Q. A thin spherical conducting shell of radius $R$ has a charge q. Another charge $Q$ is placed at the center of the shell. The electric potential at a point $P$ at distance $\frac{R}{2}$ from the center of the shell is $(Q = 10 μ C, q = - 2 μ C)$

$\frac{1.6 \times 1 0 ^{5}}{R}$ volt

$1.6 \times 1 0^{5} R$ volt

$\frac{1.4 \times 1 0 ^{5}}{R}$ volt

$\frac{4 \times 1 0 ^{- 6}}{R}$ volt

Q. A thin spherical conducting shell of radius R has a charge q. Another charge Q is placed at the center of the shell. The electric potential at a point P at distance 2R​ from the center of the shell is (Q=10μC,q=−2μC)

R1.6×105​ volt

1.6×105R volt

R1.4×105​ volt

R4×10−6​ volt

Electric potential at point P VP​=rKQ​+rKq​ VP​=2R​KQ​−2R​Kq​ VP​=R2K​(10−2)10−6 =R2×9×109×8×10−6​=R144×103​ volt VP​=R1.44×105volt​

Q. A thin spherical conducting shell of radius $R$ has a charge q. Another charge $Q$ is placed at the center of the shell. The electric potential at a point $P$ at distance $\frac{R}{2}$ from the center of the shell is $(Q = 10 μ C, q = - 2 μ C)$

$\frac{1.6 \times 1 0 ^{5}}{R}$ volt

$1.6 \times 1 0^{5} R$ volt

$\frac{1.4 \times 1 0 ^{5}}{R}$ volt

$\frac{4 \times 1 0 ^{- 6}}{R}$ volt