A thin Plano-convex glass lens (.μ = 1.5.) has its plane surface silvered and R is the radius of curvature of curved part, then which of the following ray diagram is true for an object placed at O ? ( O is at a distance of 2R from the lens)

Question

A thin Plano-convex glass lens (.μ = 1.5.) has its plane surface silvered and R is the radius of curvature of curved part, then which of the following ray diagram is true for an object placed at O ? ( O is at a distance of 2R from the lens) (A) Option 1

(B)

(C)

(D) None of the above

Tardigrade Admin · Accepted Answer

For Refraction at first surface (1.5/v)-(1/u)=(1.5 - 1/R) u=-2R, v=∞ Therefore, rays strike the mirror normally. So, by principle of reversibility, textO and text I coincide.

Q. A thin Plano-convex glass lens $(μ = 1.5)$ has its plane surface silvered and $R$ is the radius of curvature of curved part, then which of the following ray diagram is true for an object placed at $O$ ?

( $O$ is at a distance of $2 R$ from the lens)

None of the above

For Refraction at first surface $\frac{1.5}{v} - \frac{1}{u} = \frac{1.5 - 1}{R}$
$u = - 2 R,$
$v = \infty$
Therefore, rays strike the mirror normally. So, by principle of reversibility, $O$ and $I$ coincide.

Q. A thin Plano-convex glass lens (μ=1.5) has its plane surface silvered and R is the radius of curvature of curved part, then which of the following ray diagram is true for an object placed at O ? ( O is at a distance of 2R from the lens)

None of the above

For Refraction at first surface v1.5​−u1​=R1.5−1​ u=−2R, v=∞ Therefore, rays strike the mirror normally. So, by principle of reversibility, O and I coincide.

Q. A thin Plano-convex glass lens $(μ = 1.5)$ has its plane surface silvered and $R$ is the radius of curvature of curved part, then which of the following ray diagram is true for an object placed at $O$ ?

( $O$ is at a distance of $2 R$ from the lens)

For Refraction at first surface $\frac{1.5}{v} - \frac{1}{u} = \frac{1.5 - 1}{R}$
$u = - 2 R,$
$v = \infty$
Therefore, rays strike the mirror normally. So, by principle of reversibility, $O$ and $I$ coincide.