A thin metal plate P is inserted half way between the plates of a parallel plate capacitor of capacitance C in such a way that it is parallel to the two plates. The capacitance now becomes

Question

A thin metal plate P is inserted half way between the plates of a parallel plate capacitor of capacitance C in such a way that it is parallel to the two plates. The capacitance now becomes (A) C (B) ( C /2) (C) 4 C (D) None of these

Tardigrade Admin · Accepted Answer

When a thin metal plate is placed between the plates of a parallel plate capacitor, then its capacitance increases so, out of the given choices, 4 C will be the right answer.

Q. A thin metal plate $P$ is inserted half way between the plates of a parallel plate capacitor of capacitance $C$ in such a way that it is parallel to the two plates. The capacitance now becomes

$C$

$\frac{C}{2}$

$4 C$

None of these

When a thin metal plate is placed between the plates of a parallel plate capacitor, then its capacitance increases so, out of the given choices, $4 C$ will be the right answer.

Q. A thin metal plate P is inserted half way between the plates of a parallel plate capacitor of capacitance C in such a way that it is parallel to the two plates. The capacitance now becomes

C

2C​

4C

None of these

When a thin metal plate is placed between the plates of a parallel plate capacitor, then its capacitance increases so, out of the given choices, 4C will be the right answer.

Q. A thin metal plate $P$ is inserted half way between the plates of a parallel plate capacitor of capacitance $C$ in such a way that it is parallel to the two plates. The capacitance now becomes

$C$

$\frac{C}{2}$

$4 C$

When a thin metal plate is placed between the plates of a parallel plate capacitor, then its capacitance increases so, out of the given choices, $4 C$ will be the right answer.