Angle of deviation of the light ray produced by prism is, δ=A(μ−1)...(i)
where, δ= angle of deviation A= angle of prims and μ= refractive index of the prism
Given, A=3∘,δ=1∘ and μ= ?
Substituting the given values in Eq. (i), we get 1∘=3∘(μ−1)⇒μ=34=1.33
Hence, the refractive index of the prism is 1.33.