A thin bi-convex lens made out of a material of refractive index μ 1 is placed in a medium of refractive index μ 2 . A paraxial beam of light, parallel to the principal axis of the lens, is shown in the figure. Based on the ray diagram, we can conclude that

Question

A thin bi-convex lens made out of a material of refractive index μ 1 is placed in a medium of refractive index μ 2 . A paraxial beam of light, parallel to the principal axis of the lens, is shown in the figure. Based on the ray diagram, we can conclude that Question

(A) μ 1>μ 2 (B) μ 1≤ μ 2 (C) μ 1=μ 2 (D) μ 1 < μ 2

Tardigrade Admin · Accepted Answer

A bi-convex lens acts as a diverging lens when it is placed in a denser medium.

Q. A thin bi-convex lens made out of a material of refractive index $μ_{1}$ is placed in a medium of refractive index $μ_{2}$ . A paraxial beam of light, parallel to the principal axis of the lens, is shown in the figure. Based on the ray diagram, we can conclude that

$μ_{1} > μ_{2}$

$μ_{1} \leq μ_{2}$

$μ_{1} = μ_{2}$

$μ_{1} < μ_{2}$

A bi-convex lens acts as a diverging lens when it is placed in a denser medium.

Q. A thin bi-convex lens made out of a material of refractive index μ1​ is placed in a medium of refractive index μ2​ . A paraxial beam of light, parallel to the principal axis of the lens, is shown in the figure. Based on the ray diagram, we can conclude that

μ1​>μ2​

μ1​≤μ2​

μ1​=μ2​

μ1​<μ2​

A bi-convex lens acts as a diverging lens when it is placed in a denser medium.

Q. A thin bi-convex lens made out of a material of refractive index $μ_{1}$ is placed in a medium of refractive index $μ_{2}$ . A paraxial beam of light, parallel to the principal axis of the lens, is shown in the figure. Based on the ray diagram, we can conclude that

$μ_{1} > μ_{2}$

$μ_{1} \leq μ_{2}$

$μ_{1} = μ_{2}$

$μ_{1} < μ_{2}$