A thermodynamical system is changed from state (P1 , V1) to (P2 , V2) by two different processes. The quantity which will remain the same will be

Question

A thermodynamical system is changed from state (P1 , V1) to (P2 , V2) by two different processes. The quantity which will remain the same will be (A) Q (B) W (C) Q+W (D) Q-W

Tardigrade Admin · Accepted Answer

For all processes, the change in internal energy ΔU=Q-W does not change. It depends only on initial and final states.

Q. A thermodynamical system is changed from state $(P_{1}, V_{1})$ to $(P_{2}, V_{2})$ by two different processes. The quantity which will remain the same will be

$Q$

$W$

$Q + W$

$Q - W$

For all processes, the change in internal energy $Δ U = Q - W$ does not change. It depends only on initial and final states.

Q. A thermodynamical system is changed from state (P1​,V1​) to (P2​,V2​) by two different processes. The quantity which will remain the same will be

Q

W

Q+W

Q−W

For all processes, the change in internal energy ΔU=Q−W does not change. It depends only on initial and final states.

Q. A thermodynamical system is changed from state $(P_{1}, V_{1})$ to $(P_{2}, V_{2})$ by two different processes. The quantity which will remain the same will be

$Q$

$W$

$Q + W$

$Q - W$

For all processes, the change in internal energy $Δ U = Q - W$ does not change. It depends only on initial and final states.