A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height ( h /2) . The velocity versus height of the ball during its motion may be represented graphically by: (graph are drawn schematically and on not to scale)

Question

A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height ( h /2) . The velocity versus height of the ball during its motion may be represented graphically by: (graph are drawn schematically and on not to scale) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Velocity at ground (means zero height) is nonzero therefore one is incorrect and velocity versus height is non-linear therefore two is also incorrect.

v^{2} = 2 g h

v \frac{d v}{d h} = 2 g = co n s t .

\frac{d v}{d h} = \frac{constant}{v}

Here we can see slope is very high when velocity is low therefore at Maximum height the slope should be very large which is in option 3 and as velocity increases slope must decrease there for option 3 is correct.

Q. A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height 2h​. The velocity versus height of the ball during its motion may be represented graphically by : (graph are drawn schematically and on not to scale)

Q. A Tennis ball is released from a height $h$ and after freely falling on a wooden floor it rebounds and reaches height $\frac{h}{2} .$ The velocity versus height of the ball during its motion may be represented graphically by : (graph are drawn schematically and on not to scale)