A tennis ball is dropped on to the floor from a height of 9.8 m. It rebounds to a height 5.0 m. Ball comes in contact with the floor for 0.2 s. The average acceleration during contact is ms -2. (. Given g =10 ms -2 )

Question

A tennis ball is dropped on to the floor from a height of 9.8 m. It rebounds to a height 5.0 m. Ball comes in contact with the floor for 0.2 s. The average acceleration during contact is ms -2. (. Given g =10 ms -2 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

v i =√2 gh i =√2 × 10 × 9.8 downarrow =14 m / s downarrow v f =√2 gh f =√2 × 10 × 5 uparrow = 1 0 m / s uparrow | vec a avg |=|(Δ vec v /Δ t )|=(24/0.2)=120 m / s 2

Q. A tennis ball is dropped on to the floor from a height of $9.8 m$ . It rebounds to a height $5.0 m$ . Ball comes in contact with the floor for $0.2 s$ . The average acceleration during contact is ___ $m s^{- 2}$ . $($ Given $g = 10 m s^{- 2}$ )

$v_{i} = 2 g h_{i}$
$= 2 \times 10 \times 9.8 ↓$
$= 14 m / s ↓$
$v_{f} = 2 g h_{f}$
$= 2 \times 10 \times 5 ↑$
$= 10 m / s ↑$
$∣ a_{a vg} ∣ = ∣ ∣ \frac{Δ v}{Δ t} ∣ ∣ = \frac{24}{0.2} = 120 m / s^{2}$

Q. A tennis ball is dropped on to the floor from a height of 9.8m. It rebounds to a height 5.0m. Ball comes in contact with the floor for 0.2s. The average acceleration during contact is ___ms−2. ( Given g=10ms−2 )

vi​=2ghi​​ =2×10×9.8​↓ =14m/s↓ vf​=2ghf​​ =2×10×5​↑ =10m/s↑ ∣aavg​∣=∣∣​ΔtΔv​∣∣​=0.224​=120m/s2

Q. A tennis ball is dropped on to the floor from a height of $9.8 m$ . It rebounds to a height $5.0 m$ . Ball comes in contact with the floor for $0.2 s$ . The average acceleration during contact is ___ $m s^{- 2}$ . $($ Given $g = 10 m s^{- 2}$ )

$v_{i} = 2 g h_{i}$
$= 2 \times 10 \times 9.8 ↓$
$= 14 m / s ↓$
$v_{f} = 2 g h_{f}$
$= 2 \times 10 \times 5 ↑$
$= 10 m / s ↑$
$∣ a_{a vg} ∣ = ∣ ∣ \frac{Δ v}{Δ t} ∣ ∣ = \frac{24}{0.2} = 120 m / s^{2}$