A tangent galvanometer has 80 turns of wire. The internal and external diameters of the coil are 19 cm and 21 cm respectively. The reduction factor of the galvanometer at a place where H=0.32 oersted will be (1 oersted =80 A / m )

Question

A tangent galvanometer has 80 turns of wire. The internal and external diameters of the coil are 19 cm and 21 cm respectively. The reduction factor of the galvanometer at a place where H=0.32 oersted will be (1 oersted =80 A / m ) (A) 0.0064 (B) 0.64 (C) 0.064 (D) None of these

Tardigrade Admin · Accepted Answer

Reduction factor =(2 R Bh/μ0 N)=(2 × 0.1 × 0.32 × 80/80)=0.064

Q. A tangent galvanometer has $80$ turns of wire. The internal and external diameters of the coil are $19 c m$ and $21 c m$ respectively. The reduction factor of the galvanometer at a place where $H = 0.32$ oersted will be $(1$ oersted $= 80 A / m)$

0.0064

0.64

0.064

None of these

Reduction factor $= \frac{2 R B _{h}}{μ _{0} N} = \frac{2 \times 0.1 \times 0.32 \times 80}{80} = 0.064$

Q. A tangent galvanometer has 80 turns of wire. The internal and external diameters of the coil are 19cm and 21cm respectively. The reduction factor of the galvanometer at a place where H=0.32 oersted will be (1 oersted =80A/m)