A system has two charges qA = 2.5 × 10-7C and qB = -2.5 × 10-7C located at points A: (0, 0,- 15 cm) and B: (0, 0 + 15 cm) , respectively. What is the magnitude and direction of electric dipole moment of the system ?

Question

A system has two charges qA = 2.5 × 10-7C and qB = -2.5 × 10-7C located at points A: (0, 0,- 15 cm) and B: (0, 0 + 15 cm) , respectively. What is the magnitude and direction of electric dipole moment of the system ? (A)  7.5 × 10-8 cm , from positive to negative charge (B)  0.75 × 10-8 cm , from negative to positive charge (C)  7.5 × 10-8 cm , from negative to positive charge (D)  0.75 × 10-8 cm , cm, from positive to negative charge

Tardigrade Admin · Accepted Answer

qA=2.5 × 10-7C qB=-2.5 × 10-7C <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/920a5b8f728e28e80b38303a80baf809-.jpeg" /> Total charge o f the system, q=qA+qB=0 Distance between two charges at points A and B, d=15+15=30 cm=0.3 m Electric dipole moment of the system is given by, p=qA× d=qB× d =2.5 × 10-7 × 0.3 =7.5× 10-8 cm, along positive z-axis

Q. A system has two charges $q_{A} = 2.5 \times 1 0^{- 7} C$ and $q_{B} = - 2.5 \times 1 0^{- 7} C$ located at points $A : (0, 0, - 15 c m)$ and $B : (0, 0 + 15 c m)$ , respectively. What is the magnitude and direction of electric dipole moment of the system ?

$7.5 \times 1 0^{- 8} c m$ , from positive to negative charge

$0.75 \times 1 0^{- 8} c m$ , from negative to positive charge

$7.5 \times 1 0^{- 8} c m$ , from negative to positive charge

$0.75 \times 1 0^{- 8} c m$ , cm, from positive to negative charge

Q. A system has two charges qA​=2.5×10−7C and qB​=−2.5×10−7C located at points A:(0,0,−15cm) and B:(0,0+15cm) , respectively. What is the magnitude and direction of electric dipole moment of the system ?

7.5×10−8cm , from positive to negative charge

0.75×10−8cm , from negative to positive charge

7.5×10−8cm , from negative to positive charge

0.75×10−8cm , cm, from positive to negative charge

qA​=2.5×10−7C qB​=−2.5×10−7C Total charge o f the system, q=qA​+qB​=0 Distance between two charges at points A and B, d=15+15=30cm=0.3m Electric dipole moment of the system is given by, p=qA​×d=qB​×d =2.5×10−7×0.3 =7.5×10−8cm, along positive z-axis

Q. A system has two charges $q_{A} = 2.5 \times 1 0^{- 7} C$ and $q_{B} = - 2.5 \times 1 0^{- 7} C$ located at points $A : (0, 0, - 15 c m)$ and $B : (0, 0 + 15 c m)$ , respectively. What is the magnitude and direction of electric dipole moment of the system ?

$7.5 \times 1 0^{- 8} c m$ , from positive to negative charge

$0.75 \times 1 0^{- 8} c m$ , from negative to positive charge

$7.5 \times 1 0^{- 8} c m$ , from negative to positive charge

$0.75 \times 1 0^{- 8} c m$ , cm, from positive to negative charge