A symmetrical uniform solid cube of side 5 m is placed on a horizontal surface beside a vertical wall, one side of the cube is making an angle 45° with the floor as shown. If coefficient of friction μ is the same for both wall and floor, the minimum value of μ so that cube does not slip

Question

A symmetrical uniform solid cube of side 5 m is placed on a horizontal surface beside a vertical wall, one side of the cube is making an angle 45° with the floor as shown. If coefficient of friction μ is the same for both wall and floor, the minimum value of μ so that cube does not slip <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-pchv058ahgu6.png" /> (A) μ= 1 (B) μ = 0 (C) μ = (1/3) (D) Impossible to balance for any value of μ

Tardigrade Admin · Accepted Answer

At angle 45° , N and Mg balance each other, they both pass through centre of mass, so no need for friction to balance it <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-pchv058aiwf2.png" />

$μ = 1$

$μ = 0$

$μ = \frac{1}{3}$

Impossible to balance for any value of $μ$

At angle $4 5^{\circ}$ , $N$ and $M g$ balance each other, they both pass through centre of mass, so no need for friction to balance it

Q. A symmetrical uniform solid cube of side 5m is placed on a horizontal surface beside a vertical wall, one side of the cube is making an angle 45∘ with the floor as shown. If coefficient of friction μ is the same for both wall and floor, the minimum value of μ so that cube does not slip

μ=1

μ=0

μ=31​

Impossible to balance for any value of μ

At angle 45∘ , N and Mg balance each other, they both pass through centre of mass, so no need for friction to balance it

$μ = 1$

$μ = 0$

$μ = \frac{1}{3}$

Impossible to balance for any value of $μ$

At angle $4 5^{\circ}$ , $N$ and $M g$ balance each other, they both pass through centre of mass, so no need for friction to balance it