A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as: If k1=1.26×10-4 s-1, k2=3.8 ×10-5 s-1, then the percentage distributions of B and C are respectively

Question

A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as: If k1=1.26×10-4 s-1, k2=3.8 ×10-5 s-1, then the percentage distributions of B and C are respectively (A) 80 %, 20 % (B) 76.83 %, 23.17 % (C) 90 %, 10 % (D) 63.94 %, 36.06 %

Tardigrade Admin · Accepted Answer

For parallel path reaction, kaverage =k1+k2=1.26×10-4+3.8×10-5=1.64×10-4 s-1 Fractional yield of B=(k1/kaverage)=(1.26×10-4/1.64×10-4)=0.7683 Percentage distribution of B = 76.83% Fractional yield of C=(k2/kaverage)=(3.8×10-5/1.64×10-4)=0.2317 Percentage distribution of C = 23.17%

Q. A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as :
$I f k_{1} = 1.26 \times 1 0^{- 4} s^{- 1}, k_{2} = 3.8 \times 1 0^{- 5} s^{- 1},$ then the percentage distributions of B and C are respectively

$80%, 20%$

$76.83%, 23.17%$

$90%, 10%$

$63.94%, 36.06%$

Q. A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as : Ifk1​=1.26×10−4s−1,k2​=3.8×10−5s−1, then the percentage distributions of B and C are respectively

80%,20%

76.83%,23.17%

90%,10%

63.94%,36.06%

Q. A substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as :
$I f k_{1} = 1.26 \times 1 0^{- 4} s^{- 1}, k_{2} = 3.8 \times 1 0^{- 5} s^{- 1},$ then the percentage distributions of B and C are respectively

$80%, 20%$

$76.83%, 23.17%$

$90%, 10%$

$63.94%, 36.06%$