A substance breaks down by a stress of 106 N / m 2. If the density of the material of the wire is 3 × 103 kg / m 3, then the length of the wire of the substance which will break under its own weight when suspended vertically, is:

Question

A substance breaks down by a stress of 106 N / m 2. If the density of the material of the wire is 3 × 103 kg / m 3, then the length of the wire of the substance which will break under its own weight when suspended vertically, is: (A) 66.6m (B) 60.0m (C) 33,3m (D) 30.0m

Tardigrade Admin · Accepted Answer

If an external force F is applied to the cross-sectional area A of the body, then Stress =(F/A)=(m g/A) where mass in = volume x density =A l ρ Stress =(A l ρ g/A)=ρ l g =l=( text breakingstress /ρ g) Given breaking stress =106 Nm -2 ρ=3 × 103 kgm -3, g=10 ms -2 =l=(106/(3 × 103) × 10) I =33.3 m

Q. A substance breaks down by a stress of 106N/m2. If the density of the material of the wire is 3×103kg/m3, then the length of the wire of the substance which will break under its own weight when suspended vertically, is:

66.6m

60.0m

33,3m

30.0m

If an external force F is applied to the cross-sectional area A of the body, then Stress =AF​=Amg​ where mass in = volume x density =Alρ Stress =AAlρg​=ρlg =l=ρg breakingstress ​ Given breaking stress =106Nm−2 ρ=3×103kgm−3, g=10ms−2 =l=(3×103)×10106​ I=33.3m

Q. A substance breaks down by a stress of $1 0^{6} N / m^{2}$ . If the density of the material of the wire is $3 \times 1 0^{3} k g / m^{3}$ , then the length of the wire of the substance which will break under its own weight when suspended vertically, is: