A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

Question

A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by (A) √2 mg (B) √4 mg (C) √(M+m)+m g (D) √(M+m)2+M2 g

Tardigrade Admin · Accepted Answer

Free body diagram of pulley is shown in figure. Pulley is in equilibrium under four forces. Three forces as shown in figure and the fourth, which is equal and opposite to the resultant of these three forces, is the force applied by the clamp on the pulley (say

F

). Resultant

R

of these three forces is

R = ((M + m)^{2} + M^{2}) g

Therefore, the force

F

is equal and opposite to

R

as shown in figure.

∴ F = ((M + m)^{2} + M^{2}) g

∴ F=(√(M+m)2+M2) g

Q. A string of negligible mass going over a clamped pulley of mass $m$ supports a block of mass $M$ as shown in the figure. The force on the pulley by the clamp is given by

$2$ $m g$

$4$ $m g$

$(M + m) + m g$

$(M + m)^{2} + M^{2} g$

Q. A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

2​ mg

4​ mg

(M+m)+m​g

(M+m)2+M2​g

Q. A string of negligible mass going over a clamped pulley of mass $m$ supports a block of mass $M$ as shown in the figure. The force on the pulley by the clamp is given by

$2$ $m g$

$4$ $m g$

$(M + m) + m g$

$(M + m)^{2} + M^{2} g$