Q.
A string of length ℓ is fixed at both ends. It is vibrating in its 3rd overtone with maximum amplitude 'a'. The amplitude at a distance ℓ/3 from one end is.
For a string vibrating in its nth overtone (n+1)th harmonic) y=2Asin(L(n+1)πx)cosωt
Fox x=3ℓ]2A=a&n=3; y=[asin(ℓ4π⋅3ℓ)]cosωt =asin34πcosωt=−a(23)cosωt
i.e. at x=3ℓ, the amplitude is 23a