A string has a mass per unit length 5gm/m . Equation of a travelling wave on this stretched string is y=0.03sin (.450t-9x.) , where distance and time are measured in SI units. The tension in the string will be ?

Question

A string has a mass per unit length 5gm/m . Equation of a travelling wave on this stretched string is y=0.03sin (.450t-9x.) , where distance and time are measured in SI units. The tension in the string will be ? (A) 12.5N (B) 7.5N (C) 10N (D) 5N

Tardigrade Admin · Accepted Answer

k=9ω =450 ∴ v=(ω /k)=50m/s v=√(T/μ ) ∴ T=Î¼v2=502× 5× 10- 3=12.5N

Q. A string has a mass per unit length $5 g m / m$ . Equation of a travelling wave on this stretched string is $y = 0.03 s in$ $(450 t - 9 x)$ , where distance and time are measured in SI units. The tension in the string will be ?

$12.5 N$

$7.5 N$

$10 N$

$5 N$

$k = 9 ω = 450$
$∴ v = \frac{ω}{k} = 50 m / s$
$v = \frac{T}{μ}$
$∴ T = μ v^{2} = 5 0^{2} \times 5 \times 1 0^{- 3} = 12.5 N$

Q. A string has a mass per unit length 5gm/m . Equation of a travelling wave on this stretched string is y=0.03sin (450t−9x) , where distance and time are measured in SI units. The tension in the string will be ?

12.5N

7.5N

10N

5N