A straight wire of finite length carrying current I subtends an angle of 60° at point P as shown. The magnetic field at P is

Question

A straight wire of finite length carrying current I subtends an angle of 60° at point P as shown. The magnetic field at P is (A) (μ0 I/2 √3 π x) (B) (μ0 I/2 π x) (C) (√3 μ0 I/2 π x) (D) (μ0 I/3 √3 π x)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/eec230fdb14dcd4d4e0eb770bde8ffbc-.png" /> B=(μ0 I/4 π x cos 30°)[ sin 30°+ sin 30°] B=(μ0 I/4 π x((√3)2))((1/2)+(1/2)) =(μ0 i/2 √3 π x)

Q. A straight wire of finite length carrying current $I$ subtends an angle of $6 0^{\circ}$ at point $P$ as shown. The magnetic field at $P$ is

$\frac{μ _{0} I}{2 3 π x}$

$\frac{μ _{0} I}{2 π x}$

$\frac{3 μ _{0} I}{2 π x}$

$\frac{μ _{0} I}{3 3 π x}$

$B = \frac{μ _{0} I}{4 π x c o s 3 0 ^{\circ}} [sin 3 0^{\circ} + sin 3 0^{\circ}]$
$B = \frac{μ _{0} I}{4 π x ( \frac{3}{2} )} (\frac{1}{2} + \frac{1}{2})$
$= \frac{μ _{0} i}{2 3 π x}$

Q. A straight wire of finite length carrying current I subtends an angle of 60∘ at point P as shown. The magnetic field at P is

23​πxμ0​I​

2πxμ0​I​

2πx3​μ0​I​

33​πxμ0​I​