A straight wire of diameter 0.5 mm carrying a current of 1 A is replaced by another wire of 1 mm diameter carrying the same current. The strength of the magnetic field far away is

Question

A straight wire of diameter 0.5 mm carrying a current of 1 A is replaced by another wire of 1 mm diameter carrying the same current. The strength of the magnetic field far away is (A) twice the earlier value (B) same as the earlier value (C) one - half of the earlier value (D) one - quarter of the earlier value

Tardigrade Admin · Accepted Answer

The magnetic field due to a current carrying straight wire at distance

a

is given by

B = \frac{μ _{0} I}{2 πa}

So,

B \propto I

The current is same in both the wires, hence magnetic field strength will also be the same.

Q. A straight wire of diameter 0.5mm carrying a current of 1A is replaced by another wire of 1mm diameter carrying the same current. The strength of the magnetic field far away is

twice the earlier value

same as the earlier value

one - half of the earlier value

one - quarter of the earlier value

The magnetic field due to a current carrying straight wire at distance a is given by B=2πaμ0​I​ So, B∝I The current is same in both the wires, hence magnetic field strength will also be the same.

Q. A straight wire of diameter $0.5 mm$ carrying a current of $1 A$ is replaced by another wire of $1 mm$ diameter carrying the same current. The strength of the magnetic field far away is

The magnetic field due to a current carrying straight wire at distance $a$ is given by
$B = \frac{μ _{0} I}{2 πa}$
So, $B \propto I$
The current is same in both the wires, hence magnetic field strength will also be the same.