A straight line plot showing the terminal potential difference (V) of a cell as a function of current (I) drawn from it, is shown in the figure. The internal resistance of the cell would be then-

Question

A straight line plot showing the terminal potential difference (V) of a cell as a function of current (I) drawn from it, is shown in the figure. The internal resistance of the cell would be then- (A) '2.8 ohms (B) 1.4 ohms (C) 1.2 ohms (D) zero

Tardigrade Admin · Accepted Answer

I=O, V=E, ∴ E=5.6 V r =(E/I)=(5.6/2.0)=2.8 Ω

Q. A straight line plot showing the terminal potential difference (V) of a cell as a function of current (I) drawn from it, is shown in the figure. The internal resistance of the cell would be then-

'2.8 ohms

1.4 ohms

1.2 ohms

zero

$I = O, V = E,$
$∴ E = 5.6 V$
$r = \frac{E}{I} = \frac{5.6}{2.0} = 2.8Ω$

Q. A straight line plot showing the terminal potential difference (V) of a cell as a function of current (I) drawn from it, is shown in the figure. The internal resistance of the cell would be then-

'2.8 ohms

1.4 ohms

1.2 ohms

zero

I=O,V=E, ∴E=5.6V r=IE​=2.05.6​=2.8Ω

$I = O, V = E,$
$∴ E = 5.6 V$
$r = \frac{E}{I} = \frac{5.6}{2.0} = 2.8Ω$