A straight conductor of length 4 m moves at a speed of 10 m / s. When the conductor makes an angle of 30° with the direction of magnetic field of induction of 0.1 wb. per m 2 then induced emf. is :

Question

A straight conductor of length 4 m moves at a speed of 10 m / s. When the conductor makes an angle of 30° with the direction of magnetic field of induction of 0.1 wb. per m 2 then induced emf. is : (A) 8 V (B) 4 V (C) 1 V (D) 2 V

Tardigrade Admin · Accepted Answer

Induced emf is given by e=B v l sin θ=0.1 × 10 × 4 sin 30° e=2 volt

Q. A straight conductor of length $4 m$ moves at a speed of $10 m / s$ . When the conductor makes an angle of $3 0^{\circ}$ with the direction of magnetic field of induction of $0.1 w b$ . per $m^{2}$ then induced emf. is :

8 V

4 V

1 V

2 V

Induced emf is given by
$e = B v l sin θ = 0.1 \times 10 \times 4 sin 3 0^{\circ}$
$e = 2$ volt

Q. A straight conductor of length 4m moves at a speed of 10m/s. When the conductor makes an angle of 30∘ with the direction of magnetic field of induction of 0.1wb. per m2 then induced emf. is :

8 V

4 V

1 V

2 V

Induced emf is given by e=Bvlsinθ=0.1×10×4sin30∘ e=2 volt

Q. A straight conductor of length $4 m$ moves at a speed of $10 m / s$ . When the conductor makes an angle of $3 0^{\circ}$ with the direction of magnetic field of induction of $0.1 w b$ . per $m^{2}$ then induced emf. is :

Induced emf is given by
$e = B v l sin θ = 0.1 \times 10 \times 4 sin 3 0^{\circ}$
$e = 2$ volt