A stone is dropped from the top of a tower of height h After 1 s another stone is dropped from the balcony 20 m below the top. Both reach the bottom simultaneously. What is the value o f h in (m) ? Take g = 10 ms-2

Question

A stone is dropped from the top of a tower of height h After 1 s another stone is dropped from the balcony 20 m below the top. Both reach the bottom simultaneously. What is the value o f h in (m) ? Take g = 10 ms-2 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

h=(1/2)gt2 and h-20=(1/2)g (t-1)2 Solving them, we get t=2.5 s and h=31.25 m

Q. A stone is dropped from the top of a tower of height $h$ After $1 s$ another stone is dropped from the balcony $20 m$ below the top. Both reach the bottom simultaneously. What is the value o f $h$ in $(m)$ ? Take $g = 10 m s^{- 2}$

$h = \frac{1}{2} g t^{2}$ and $h - 20 = \frac{1}{2} g (t - 1)^{2}$
Solving them, we get $t = 2.5 s$ and $h = 31.25 m$

Q. A stone is dropped from the top of a tower of height h After 1s another stone is dropped from the balcony 20m below the top. Both reach the bottom simultaneously. What is the value o f h in (m) ? Take g=10ms−2

h=21​gt2 and h−20=21​g(t−1)2 Solving them, we get t=2.5s and h=31.25m

Q. A stone is dropped from the top of a tower of height $h$ After $1 s$ another stone is dropped from the balcony $20 m$ below the top. Both reach the bottom simultaneously. What is the value o f $h$ in $(m)$ ? Take $g = 10 m s^{- 2}$

$h = \frac{1}{2} g t^{2}$ and $h - 20 = \frac{1}{2} g (t - 1)^{2}$
Solving them, we get $t = 2.5 s$ and $h = 31.25 m$