A stone is attached to one end of a string and rotated in a vertical circle. If string breaks at the position of maximum tension, it will break at

Question

A stone is attached to one end of a string and rotated in a vertical circle. If string breaks at the position of maximum tension, it will break at <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0628535beb6ea8b6822ff1a8f7ac5c2a-.png" /> (A) A (B) B (C) C (D) D

Tardigrade Admin · Accepted Answer

The body describing a vertical circle <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/47951177d5c4b649bcfb4cbf02e6749a-.png" /> ∴ T-mg cos θ=(m v2/R) ⇒ T = mg cos θ+( mv 2/ R ) Tension is maximum when cos θ=1 and velocity is maximum. Both conditions are satisfied at θ=0°, i.e. at lowest point B.

Q. A stone is attached to one end of a string and rotated in a vertical circle. If string breaks at the position of maximum tension, it will break at

A

B

C

D

The body describing a vertical circle

$∴ T - m g cos θ = \frac{m v ^{2}}{R}$
$\Rightarrow T = m g cos θ + \frac{m v ^{2}}{R}$
Tension is maximum when $cos θ = 1$ and velocity is maximum. Both conditions are satisfied at $θ = 0^{\circ}$ , i.e. at lowest point $B$ .

Q. A stone is attached to one end of a string and rotated in a vertical circle. If string breaks at the position of maximum tension, it will break at

A

B

C

D

The body describing a vertical circle ∴T−mgcosθ=Rmv2​ ⇒T=mgcosθ+Rmv2​ Tension is maximum when cosθ=1 and velocity is maximum. Both conditions are satisfied at θ=0∘, i.e. at lowest point B.

The body describing a vertical circle

$∴ T - m g cos θ = \frac{m v ^{2}}{R}$
$\Rightarrow T = m g cos θ + \frac{m v ^{2}}{R}$
Tension is maximum when $cos θ = 1$ and velocity is maximum. Both conditions are satisfied at $θ = 0^{\circ}$ , i.e. at lowest point $B$ .