A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The displacement (in metre) of the stone from the point of release after 10 sec is

Question

A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The displacement (in metre) of the stone from the point of release after 10 sec is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

u = 12 m/s, g = 9.8 m/sec2, t = 10 sec Displacement = ut + (1/2) gt2 = 12 × 10 + (1/2) × 9.8 × 100 = 610 m

Q. A stone falls from a balloon that is descending at a uniform rate of $12 m / s$ . The displacement (in metre) of the stone from the point of release after $10$ sec is

$u = 12 m / s, g = 9.8 m / se c^{2}, t = 10 sec$
Displacement $= u t + \frac{1}{2} g t^{2}$
$= 12 \times 10 + \frac{1}{2} \times 9.8 \times 100 = 610 m$

Q. A stone falls from a balloon that is descending at a uniform rate of 12m/s. The displacement (in metre) of the stone from the point of release after 10 sec is

u=12m/s,g=9.8m/sec2,t=10sec Displacement =ut+21​gt2 =12×10+21​×9.8×100=610m

Q. A stone falls from a balloon that is descending at a uniform rate of $12 m / s$ . The displacement (in metre) of the stone from the point of release after $10$ sec is

$u = 12 m / s, g = 9.8 m / se c^{2}, t = 10 sec$
Displacement $= u t + \frac{1}{2} g t^{2}$
$= 12 \times 10 + \frac{1}{2} \times 9.8 \times 100 = 610 m$