A stationary object explodes into masses m1 and m2. They move in opposite directions with velocities V1 and V2. The ratio of kinetic energy E1 to kinetic energy E2 is

Question

A stationary object explodes into masses m1 and m2. They move in opposite directions with velocities V1 and V2. The ratio of kinetic energy E1 to kinetic energy E2 is (A) (m2/m1) (B) (m1/m2) (C) (2m2/m1) (D) (2m1/m2)

Tardigrade Admin · Accepted Answer

As stationary object explodes into mases m1 and m2 and move in opposite direction According to conservation of momentum m1 v1=-m2 v2 ⇒ (v1/v2)=(-m2/m1) Now, ratio of KE ( KE 1/ KE 2)=(1 / 2 m1 v12/1 / 2 m2 v22)=(m1/m2)[(m2/m1)]2=(m2/m1)

Q. A stationary object explodes into masses $m_{1}$ and $m_{2}$ . They move in opposite directions with velocities $V_{1}$ and $V_{2}$ . The ratio of kinetic energy $E_{1}$ to kinetic energy $E_{2}$ is

$\frac{m _{2}}{m _{1}}$

$\frac{m _{1}}{m _{2}}$

$\frac{2 m _{2}}{m _{1}}$

$\frac{2 m _{1}}{m _{2}}$

Q. A stationary object explodes into masses m1​ and m2​. They move in opposite directions with velocities V1​ and V2​. The ratio of kinetic energy E1​ to kinetic energy E2​ is

m1​m2​​

m2​m1​​

m1​2m2​​

m2​2m1​​

As stationary object explodes into mases m1​ and m2​ and move in opposite direction According to conservation of momentum m1​v1​=−m2​v2​⇒v2​v1​​=m1​−m2​​ Now, ratio of KE KE2​KE1​​=1/2m2​v22​1/2m1​v12​​=m2​m1​​[m1​m2​​]2=m1​m2​​

Q. A stationary object explodes into masses $m_{1}$ and $m_{2}$ . They move in opposite directions with velocities $V_{1}$ and $V_{2}$ . The ratio of kinetic energy $E_{1}$ to kinetic energy $E_{2}$ is

$\frac{m _{2}}{m _{1}}$

$\frac{m _{1}}{m _{2}}$

$\frac{2 m _{2}}{m _{1}}$

$\frac{2 m _{1}}{m _{2}}$