A stationary bomb explodes into two parts of masses in the ratio of 1:3 . If the heavier mass moves with a velocity 4 m/s, what is the velocity of lighter part?

Question

A stationary bomb explodes into two parts of masses in the ratio of 1:3 . If the heavier mass moves with a velocity 4 m/s, what is the velocity of lighter part? (A)  12 ms-1 opposite to heavier mass (B)  12 ms-1 in the direction of heavier mass (C) 6 ms-1 opposite to heavier mass (D) 6 ms-1 in the direction of heavier mass

Tardigrade Admin · Accepted Answer

The ratio of masses =1: 3 Therefore, m1=x kg, m2=3 x kg Applying law of conservation of momentum m1 v1+m2 v2=0 ⇒ x × v1+3 x × 4=0 ⇒ v1=-12 m / s Therefore, velocity of lighter mass is opposite to that of heavier mass.

Q. A stationary bomb explodes into two parts of masses in the ratio of $1 : 3$ . If the heavier mass moves with a velocity $4 m / s,$ what is the velocity of lighter part?

$12 m s^{- 1}$ opposite to heavier mass

$12 m s^{- 1}$ in the direction of heavier mass

$6 m s^{- 1}$ opposite to heavier mass

$6 m s^{- 1}$ in the direction of heavier mass

The ratio of masses $= 1 : 3$
Therefore, $m_{1} = x k g, m_{2} = 3 x k g$
Applying law of conservation of momentum
$m_{1} v_{1} + m_{2} v_{2} = 0$
$\Rightarrow x \times v_{1} + 3 x \times 4 = 0$
$\Rightarrow v_{1} = - 12 m / s$
Therefore, velocity of lighter mass is opposite to that of heavier mass.

Q. A stationary bomb explodes into two parts of masses in the ratio of 1:3 . If the heavier mass moves with a velocity 4m/s, what is the velocity of lighter part?

12ms−1 opposite to heavier mass

12ms−1 in the direction of heavier mass

6ms−1 opposite to heavier mass

6ms−1 in the direction of heavier mass

The ratio of masses =1:3 Therefore, m1​=xkg,m2​=3xkg Applying law of conservation of momentum m1​v1​+m2​v2​=0 ⇒x×v1​+3x×4=0 ⇒v1​=−12m/s Therefore, velocity of lighter mass is opposite to that of heavier mass.

Q. A stationary bomb explodes into two parts of masses in the ratio of $1 : 3$ . If the heavier mass moves with a velocity $4 m / s,$ what is the velocity of lighter part?

$12 m s^{- 1}$ opposite to heavier mass

$12 m s^{- 1}$ in the direction of heavier mass

$6 m s^{- 1}$ opposite to heavier mass

$6 m s^{- 1}$ in the direction of heavier mass