A stationary body of mass m explodes into 3 parts of masses m in the ratio 1: 3: 3, its two fractions having equal masses moving at right angles to each other with a velocity of 15 ms-1. What is the velocity of the third body

Question

A stationary body of mass m explodes into 3 parts of masses m in the ratio 1: 3: 3, its two fractions having equal masses moving at right angles to each other with a velocity of 15 ms-1. What is the velocity of the third body (A) √2 ms-1 (B) 5 ms-1 (C) 5√32 ms-1 (D) none of these

Tardigrade Admin · Accepted Answer

Applying law of conservation of momentum, we get √2 p = p3 i.e. √2 × 3m × 15 = m × upsilon i.e. upsilon = 45√2 m s-1

Q. A stationary body of mass m explodes into 3 parts of masses m in the ratio 1 : 3 : 3, its two fractions having equal masses moving at right angles to each other with a velocity of 15 $m s^{- 1}$ . What is the velocity of the third body

$2 m s^{- 1}$

$5 m s^{- 1}$

$532 m s^{- 1}$

none of these

Applying law of conservation of momentum, we get
$2 p = p_{3}$ i.e. $2 \times 3 m \times 15 = m \times υ$ i.e. $υ = 452 m s^{- 1}$

Q. A stationary body of mass m explodes into 3 parts of masses m in the ratio 1 : 3 : 3, its two fractions having equal masses moving at right angles to each other with a velocity of 15 ms−1. What is the velocity of the third body

2​ms−1

5ms−1

532​ms−1