A square shaped coil of area 70 cm 2 having 600 turns rotates in a magnetic field of 0.4 wbm -2, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field. If the coil completes 500 revolution in a minute, the instantaneous emf when the plane of the coil is inclined at 60° with the field, will be V .(. Take .π=(22/7))

Question

A square shaped coil of area 70 cm 2 having 600 turns rotates in a magnetic field of 0.4 wbm -2, about an axis which is parallel to one of the side of the coil and perpendicular to the direction of field. If the coil completes 500 revolution in a minute, the instantaneous emf when the plane of the coil is inclined at 60° with the field, will be V .(. Take .π=(22/7)) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

N =600, A =70 × 10-4 m 2, B =0.4 T ω=(500 × 2 π/60)=(100 π/6) rad / s E = NAB ω sin ω t ω t text is angle b / w vec A vec B =600 × 70 × 10-4 × 0.4 × (100 π/6) × (1/2) =44 V

N=600,A=70×10−4m2,B=0.4T ω=60500×2π​=6100π​rad/s E=NABωsinωt ωt is angle b/wA&B =600×70×10−4×0.4×6100π​×21​ =44V

$N = 600, A = 70 \times 1 0^{- 4} m^{2}, B = 0.4 T$
$ω = \frac{500 \times 2 π}{60} = \frac{100 π}{6} r a d / s$
$E = N A B ω sin ω t$
$ω t is angle b / w A & B$
$= 600 \times 70 \times 1 0^{- 4} \times 0.4 \times \frac{100 π}{6} \times \frac{1}{2}$
$= 44 V$