A square plate of 0.5 m side length parallel to a second plate with a velocity of 0.5 m / s, both plates being immersed in water. If the viscous force is 0.081 N and the coefficient of viscosity is 0.02 poise, distance between the plates in cm is

Question

A square plate of 0.5 m side length parallel to a second plate with a velocity of 0.5 m / s, both plates being immersed in water. If the viscous force is 0.081 N and the coefficient of viscosity is 0.02 poise, distance between the plates in cm is (A) 2.14 cm (B) 1 cm (C) 3.08 cm (D) 0.4 cm

Tardigrade Admin · Accepted Answer

F =η ( Adv / dx ) ⇒ dx =η ( Adv / F) =(0.02 × 0.25 × 0.5/0.081) ∴ dx =0.0308=3.08 cm

Q. A square plate of $0.5 m$ side length parallel to a second plate with a velocity of $0.5 m / s$ , both plates being immersed in water. If the viscous force is $0.081 N$ and the coefficient of viscosity is $0.02$ poise, distance between the plates in $c m$ is

$2.14 c m$

$1 c m$

$3.08 c m$

$0.4 c m$

$F = η \frac{A d v}{d x}$
$\Rightarrow d x = η \frac{A d v}{F}$
$= \frac{0.02 \times 0.25 \times 0.5}{0.081}$
$∴ d x = 0.0308 = 3.08 c m$

Q. A square plate of 0.5m side length parallel to a second plate with a velocity of 0.5m/s, both plates being immersed in water. If the viscous force is 0.081N and the coefficient of viscosity is 0.02 poise, distance between the plates in cm is

2.14cm

1cm

3.08cm

0.4cm