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Q. A square plate of $0.5 m$ side length parallel to a second plate with a velocity of $0.5 m / s$, both plates being immersed in water. If the viscous force is $0.081 N$ and the coefficient of viscosity is $0.02$ poise, distance between the plates in $cm$ is

Mechanical Properties of Fluids

Solution:

$F =\eta \frac{ Adv }{ dx } $
$\Rightarrow dx =\eta \frac{ Adv }{ F}$
$=\frac{0.02 \times 0.25 \times 0.5}{0.081}$
$\therefore dx =0.0308=3.08 cm$