A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is :

Question

A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is : (A) zero weber (B) 2 weber (C) 0.5 weber (D) 1 weber

Tardigrade Admin · Accepted Answer

B=0.5 T Angle between vecB vecA is zero φ = B.A. cos 0 =0.5 ×(1) × 1 =0.5 Wb

Q. A square loop of side $1 m$ and resistance $1 Ω$ is placed in a magnetic field of $0.5 T$ . If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is :

zero weber

$2$ weber

$0.5$ weber

$1$ weber

$B = 0.5 T$
Angle between $B & A$ is zero
$ϕ =$ B.A. $cos 0$
$= 0.5 \times (1) \times 1$
$= 0.5 Wb$

Q. A square loop of side 1m and resistance 1Ω is placed in a magnetic field of 0.5T. If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is :

zero weber

2 weber

0.5 weber

1 weber

B=0.5T Angle between B&A is zero ϕ= B.A. cos0 =0.5×(1)×1 =0.5Wb

Q. A square loop of side $1 m$ and resistance $1 Ω$ is placed in a magnetic field of $0.5 T$ . If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is :

$2$ weber

$0.5$ weber

$1$ weber

$B = 0.5 T$
Angle between $B & A$ is zero
$ϕ =$ B.A. $cos 0$
$= 0.5 \times (1) \times 1$
$= 0.5 Wb$