A square lead slab of side 1 metre and thickness 1 metre is subjected to a shearing force on its narrow edge of 15 × 104 N. The lower edge is riveted to the floor. How much will the upper edge be displaced? (G=5.6 × 109 N / m 2)

Question

A square lead slab of side 1 metre and thickness 1 metre is subjected to a shearing force on its narrow edge of 15 × 104 N. The lower edge is riveted to the floor. How much will the upper edge be displaced? (G=5.6 × 109 N / m 2) (A) 26 μ m (B) 30 μ m (C) 21 μ m (D) None

Tardigrade Admin · Accepted Answer

∴ G=(F × L/A × Δ L) ∴ Δ L=(F × L/A × G) =(15 × 104 × 1/1 × 5.6 × 109) =2.6 × 10-5 m

Q. A square lead slab of side 1 metre and thickness 1 metre is subjected to a shearing force on its narrow edge of $15 \times 1 0^{4} N$ . The lower edge is riveted to the floor. How much will the upper edge be displaced?
$(G = 5.6 \times 1 0^{9} N / m^{2})$

$26 μ m$

$30 μ m$

$21 μ m$

None

$∴ G = \frac{F \times L}{A \times Δ L}$
$∴ Δ L = \frac{F \times L}{A \times G}$
$= \frac{15 \times 1 0 ^{4} \times 1}{1 \times 5.6 \times 1 0 ^{9}}$
$= 2.6 \times 1 0^{- 5} m$

Q. A square lead slab of side 1 metre and thickness 1 metre is subjected to a shearing force on its narrow edge of 15×104N. The lower edge is riveted to the floor. How much will the upper edge be displaced? (G=5.6×109N/m2)

26μm

30μm

21μm