Question

A square aluminium (shear modulus is $25\times 10^{9}N{m}^{-2}$ ) slab of side $60cm$ and thickness $15cm$ is subjected to a shearing force (on its narrow face) of $18.0\times 10^{4}N$. The lower edge is riveted to the floor. The displacement of the upper edge is ______$\mu m$.

Answer 1

Answer: 48

$\frac{F}{A}=\eta \frac{x}{\ell }\Rightarrow \frac{F\ell }{A\eta }=x$
$\Rightarrow x=\frac{18\times 10^4\times 60\times 10^{-2}}{60\times 10^{-2}\times 15\times 10^{-2}\times 25\times 10^9}$
$=48\times 10^{-6}m=48\mu m$