A spring of force constant k is cut into three equal parts and then they are suspended from the same point. The force constant of the system is:

Question

A spring of force constant k is cut into three equal parts and then they are suspended from the same point. The force constant of the system is: (A) k (B) 3k (C) 9k (D)  (k/9)

Tardigrade Admin · Accepted Answer

We know that when a spring is cut into three equal parts, then the force constant of each part is 3k. Now these are suspended from the same point as a result of this these are connected in parallel. Hence k textparallel=3k+3k+3k=9k

Q. A spring of force constant k is cut into three equal parts and then they are suspended from the same point. The force constant of the system is:

k

3k

9k

$\frac{k}{9}$

We know that when a spring is cut into three equal parts, then the force constant of each part is 3k. Now these are suspended from the same point as a result of this these are connected in parallel. Hence $k_{parallel} = 3 k + 3 k + 3 k = 9 k$

Q. A spring of force constant k is cut into three equal parts and then they are suspended from the same point. The force constant of the system is:

k

3k

9k

9k​

We know that when a spring is cut into three equal parts, then the force constant of each part is 3k. Now these are suspended from the same point as a result of this these are connected in parallel. Hence kparallel​=3k+3k+3k=9k

$\frac{k}{9}$

We know that when a spring is cut into three equal parts, then the force constant of each part is 3k. Now these are suspended from the same point as a result of this these are connected in parallel. Hence $k_{parallel} = 3 k + 3 k + 3 k = 9 k$