A spring block system in horizontal oscillation has a time-period T. Now the spring is cut into four equal parts and the block is re-connected with one of the parts. The new time period of vertical oscillation will be

Question

A spring block system in horizontal oscillation has a time-period T. Now the spring is cut into four equal parts and the block is re-connected with one of the parts. The new time period of vertical oscillation will be (A) (T/√2) (B) 2 T (C) (T/2) (D) (T/2 √2)

Tardigrade Admin · Accepted Answer

When spring is cut into 4 parts. The spring constant of each part will become 4 k. T2=2 π √(m/4 k) T2=(T/2)

Q. A spring block system in horizontal oscillation has a time-period $T$ . Now the spring is cut into four equal parts and the block is re-connected with one of the parts. The new time period of vertical oscillation will be

$\frac{T}{2}$

$2 T$

$\frac{T}{2}$

$\frac{T}{2 2}$

When spring is cut into $4$ parts.
The spring constant of each part will become $4 k$ .
$T_{2} = 2 π \frac{m}{4 k}$
$T_{2} = \frac{T}{2}$

Q. A spring block system in horizontal oscillation has a time-period T. Now the spring is cut into four equal parts and the block is re-connected with one of the parts. The new time period of vertical oscillation will be

2​T​

2T

2T​

22​T​

When spring is cut into 4 parts. The spring constant of each part will become 4k. T2​=2π4km​​ T2​=2T​

Q. A spring block system in horizontal oscillation has a time-period $T$ . Now the spring is cut into four equal parts and the block is re-connected with one of the parts. The new time period of vertical oscillation will be

$\frac{T}{2}$

$2 T$

$\frac{T}{2}$

$\frac{T}{2 2}$

When spring is cut into $4$ parts.
The spring constant of each part will become $4 k$ .
$T_{2} = 2 π \frac{m}{4 k}$
$T_{2} = \frac{T}{2}$