A sphere of radius R has a uniform distribution of electric charge in its volume. At a distance x from its centre for x

Question

A sphere of radius R has a uniform distribution of electric charge in its volume. At a distance x from its centre for x < R, the electric field is directly proportional to (A) (1/x2) (B) (1/x) (C) x (D) x2

Tardigrade Admin · Accepted Answer

In non-conducting sphere, If x < R (radius) then E=(k Q x/R3) Or E propto x

Q. A sphere of radius $R$ has a uniform distribution of electric charge in its volume. At a distance $x$ from its centre for $x < R$ , the electric field is directly proportional to

$\frac{1}{x ^{2}}$

$\frac{1}{x}$

$x$

$x^{2}$

In non-conducting sphere,
If $x < R$ (radius)
then $E = \frac{k Q x}{R ^{3}}$
Or $E \propto x$

Q. A sphere of radius R has a uniform distribution of electric charge in its volume. At a distance x from its centre for x<R, the electric field is directly proportional to

x21​

x1​

x

x2

In non-conducting sphere, If x<R (radius) then E=R3kQx​ Or E∝x

Q. A sphere of radius $R$ has a uniform distribution of electric charge in its volume. At a distance $x$ from its centre for $x < R$ , the electric field is directly proportional to

$\frac{1}{x ^{2}}$

$\frac{1}{x}$

$x$

$x^{2}$

In non-conducting sphere,
If $x < R$ (radius)
then $E = \frac{k Q x}{R ^{3}}$
Or $E \propto x$