A sound wave of frequency 500 Hz covers a distance of 1000 m in 5 second between the points X and Y. Then the number of waves between X and Y is:

Question

A sound wave of frequency 500 Hz covers a distance of 1000 m in 5 second between the points X and Y. Then the number of waves between X and Y is: (A) 500 (B) 1000 (C) 2500 (D) 5000

Tardigrade Admin · Accepted Answer

V=(1000/5)=200 m / s V=n λ ⇒ λ =(V/n)=(200/500) No. of waves =(L/λ) =(1000 × 500/200) =2500

Q. A sound wave of frequency $500 Hz$ covers a distance of $1000 m$ in $5$ second between the points X and Y. Then the number of waves between X and Y is:

500

1000

2500

5000

$V = \frac{1000}{5} = 200 m / s$
$V = nλ \Rightarrow λ$
$= \frac{V}{n} = \frac{200}{500}$
No. of waves $= \frac{L}{λ}$
$= \frac{1000 \times 500}{200}$
$= 2500$

Q. A sound wave of frequency 500Hz covers a distance of 1000m in 5 second between the points X and Y. Then the number of waves between X and Y is:

500

1000

2500

5000

V=51000​=200m/s V=nλ⇒λ =nV​=500200​ No. of waves =λL​ =2001000×500​ =2500

Q. A sound wave of frequency $500 Hz$ covers a distance of $1000 m$ in $5$ second between the points X and Y. Then the number of waves between X and Y is:

$V = \frac{1000}{5} = 200 m / s$
$V = nλ \Rightarrow λ$
$= \frac{V}{n} = \frac{200}{500}$
No. of waves $= \frac{L}{λ}$
$= \frac{1000 \times 500}{200}$
$= 2500$