1. Tardigrade
  2. Question
  3. Physics
  4. A sound wave of frequency 500 Hz covers a distance of 1000 m in 5 second between the points X and Y. Then the number of waves between X and Y is:

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A sound wave of frequency $500\, Hz$ covers a distance of $1000\, m$ in $5$ second between the points X and Y. Then the number of waves between X and Y is:

Waves

Solution:

$V=\frac{1000}{5}=200\, m / s$
$V=n \lambda \Rightarrow \lambda$
$=\frac{V}{n}=\frac{200}{500}$
No. of waves $=\frac{L}{\lambda}$
$=\frac{1000 \times 500}{200}$
$=2500$