Question

A solution wiht $pH=2$ is more acidic than one with a $pH=6$, by a factor

• A. 4000
• B. 5000
• C. 8000
• D. 10000

Answer 1

Answer: (D)

$pH=-log\left[H^{+}\right]$

$\Rightarrow 2=-log{\left[H^{+}\right]}_1,$ and $6=-log{\left[H^{+}\right]}_2$

$\Rightarrow \frac{log{\left[H^{+}\right]}_1}{log{\left[H^{+}\right]}_2}=\frac{10^{-2}}{10^{-6}}=10^4=10,000$

Therefore, acidity is more in pH=2 than pH=6 by an order of 10,000.