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  4. A solution wiht pH = 2 is more acidic than one with a pH = 6, by a factor

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Q. A solution wiht $pH = 2$ is more acidic than one with a $pH = 6$, by a factor

AIIMSAIIMS 1997Equilibrium

Solution:

$pH = -log \left[H^{+}\right]$

$\Rightarrow 2 = -log \left[H ^{+}\right]_{1},$ and $6 = - log \left[H^{+} \right]_{2}$

$\Rightarrow \frac{log\left[H^{+}\right]_{1}}{log\left[H^{+}\right]_{2}}=\frac{10^{-2}}{10^{-6}}=10^{4}=10,000$

Therefore, acidity is more in pH=2 than pH=6 by an order of 10,000.