A solution of sucrose (molar mass =342 ) is prepared by dissolving 68.4 g in 1000 g of water. Calculate The vapour pressure of solution at 293 K

Question

A solution of sucrose (molar mass =342 ) is prepared by dissolving 68.4 g in 1000 g of water. Calculate The vapour pressure of solution at 293 K (A) 0.0229 (B) 0.4 (C) 0.6 (D) 0.9

Tardigrade Admin · Accepted Answer

Vapour Pressure of solution can be calculated from the relation:

\frac{P _{A} ^{\circ} - P _{A}}{P _{A}^{\circ}} = χ_{B} = \frac{W _{B} / M w _{B}}{W _{A} / M w _{A}}

Here

W_{A} = 1000 g, W_{A} = 68.4 g, P_{A}^{\circ} = 0.023 a t m

,

M w_{A} = 18, M w_{B} = 342

Substituting the values, we get

\frac{0.023 - P _{A}}{0.023} = \frac{68.4/342}{1000/18}

or

\frac{0.023 - P _{A}}{0.023} = \frac{68.4 \times 18}{342 \times 100}

or

\frac{0.023 - P _{A}}{0.023} = 0.0036

or

0.023 - P_{A} = 0.0036 \times 0.023 = 0.000083

P_{A} = 0.023 - 0.00008 = 0.02292 a t m

Vapor pressure of solution

= 0.02292 a t m

Q. A solution of sucrose (molar mass $= 342$ ) is prepared by dissolving $68.4 g$ in $1000 g$ of water. Calculate
The vapour pressure of solution at $293 K$

$0.0229$

$0.4$

$0.6$

$0.9$

Q. A solution of sucrose (molar mass =342 ) is prepared by dissolving 68.4g in 1000g of water. Calculate The vapour pressure of solution at 293K

0.0229

0.4

0.6

0.9

Q. A solution of sucrose (molar mass $= 342$ ) is prepared by dissolving $68.4 g$ in $1000 g$ of water. Calculate
The vapour pressure of solution at $293 K$

$0.0229$

$0.4$

$0.6$

$0.9$