A solution of sodium sulfate contains 92 g of Na+ ions per kilogram of water. The molality of Na+ ions in that solution in mol kg-1 is:

Question

A solution of sodium sulfate contains 92 g of Na+ ions per kilogram of water. The molality of Na+ ions in that solution in mol kg-1 is: (A) 16 (B) 8 (C) 4 (D) 12

Tardigrade Admin · Accepted Answer

nNa+ = (92/23) = 4 So molality = 4

Q. A solution of sodium sulfate contains $92 g$ of $N a^{+}$ ions per kilogram of water. The molality of $N a^{+}$ ions in that solution in $m o l k g^{- 1}$ is:

16

8

4

12

$n_{N a^{+}} = \frac{92}{23} = 4$
So molality = 4

Q. A solution of sodium sulfate contains 92g of Na+ ions per kilogram of water. The molality of Na+ ions in that solution in molkg−1 is:

16

8

4

12

nNa+​=2392​=4 So molality = 4

Q. A solution of sodium sulfate contains $92 g$ of $N a^{+}$ ions per kilogram of water. The molality of $N a^{+}$ ions in that solution in $m o l k g^{- 1}$ is:

$n_{N a^{+}} = \frac{92}{23} = 4$
So molality = 4