A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The mass percentage of carbon in P is ldots ldots . % (Round off the answer to the nearest whole number) (Atomic mass: C=12;H=1;O=16 )

Question

A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The mass percentage of carbon in P is ldots ldots . % (Round off the answer to the nearest whole number) (Atomic mass: C=12;H=1;O=16 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-v1xzs8adfaxsyqy7.jpg" /> mass of Salicylaldehyde =12× 7+6× 1+16× 2=122 mass of carbon =12× 7=84 The mass % of carbon =(84/122)× 100=68.85 %

Q. A solution of phenol in chloroform when treated with aqueous $N a O H$ gives compound $P$ as a major product. The mass percentage of carbon in $P$ is $\dots\dots .$ %
(Round off the answer to the nearest whole number)
(Atomic mass : $C = 12; H = 1; O = 16$ )

mass of Salicylaldehyde $= 12 \times 7 + 6 \times 1 + 16 \times 2 = 122$
mass of carbon $= 12 \times 7 = 84$
The mass $%$ of carbon $= \frac{84}{122} \times 100 = 68.85%$

Q. A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The mass percentage of carbon in P is ……. % (Round off the answer to the nearest whole number) (Atomic mass : C=12;H=1;O=16 )

mass of Salicylaldehyde =12×7+6×1+16×2=122 mass of carbon =12×7=84 The mass % of carbon =12284​×100=68.85%

Q. A solution of phenol in chloroform when treated with aqueous $N a O H$ gives compound $P$ as a major product. The mass percentage of carbon in $P$ is $\dots\dots .$ %
(Round off the answer to the nearest whole number)
(Atomic mass : $C = 12; H = 1; O = 16$ )

mass of Salicylaldehyde $= 12 \times 7 + 6 \times 1 + 16 \times 2 = 122$
mass of carbon $= 12 \times 7 = 84$
The mass $%$ of carbon $= \frac{84}{122} \times 100 = 68.85%$